146 lines
4.2 KiB
C
146 lines
4.2 KiB
C
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/* @(#)k_tan.c 5.1 93/09/24 */
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/*
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* ====================================================
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* Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
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*
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* Developed at SunPro, a Sun Microsystems, Inc. business.
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* Permission to use, copy, modify, and distribute this
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* software is freely granted, provided that this notice
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* is preserved.
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* ====================================================
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*/
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/* __kernel_tan( x, y, k )
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* kernel tan function on [-pi/4, pi/4], pi/4 ~ 0.7854
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* Input x is assumed to be bounded by ~pi/4 in magnitude.
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* Input y is the tail of x.
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* Input k indicates whether tan (if k=1) or
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* -1/tan (if k= -1) is returned.
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*
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* Algorithm
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* 1. Since tan(-x) = -tan(x), we need only to consider positive x.
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* 2. if x < 2^-28 (hx<0x3e300000 0), return x with inexact if x!=0.
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* 3. tan(x) is approximated by a odd polynomial of degree 27 on
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* [0,0.67434]
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* 3 27
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* tan(x) ~ x + T1*x + ... + T13*x
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* where
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*
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* |tan(x) 2 4 26 | -59.2
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* |----- - (1+T1*x +T2*x +.... +T13*x )| <= 2
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* | x |
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*
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* Note: tan(x+y) = tan(x) + tan'(x)*y
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* ~ tan(x) + (1+x*x)*y
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* Therefore, for better accuracy in computing tan(x+y), let
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* 3 2 2 2 2
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* r = x *(T2+x *(T3+x *(...+x *(T12+x *T13))))
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* then
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* 3 2
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* tan(x+y) = x + (T1*x + (x *(r+y)+y))
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*
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* 4. For x in [0.67434,pi/4], let y = pi/4 - x, then
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* tan(x) = tan(pi/4-y) = (1-tan(y))/(1+tan(y))
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* = 1 - 2*(tan(y) - (tan(y)^2)/(1+tan(y)))
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*/
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#include "fdlibm.h"
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#ifndef _DOUBLE_IS_32BITS
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#ifdef __STDC__
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static const double
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#else
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static double
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#endif
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one = 1.00000000000000000000e+00, /* 0x3FF00000, 0x00000000 */
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pio4 = 7.85398163397448278999e-01, /* 0x3FE921FB, 0x54442D18 */
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pio4lo= 3.06161699786838301793e-17, /* 0x3C81A626, 0x33145C07 */
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T[] = {
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3.33333333333334091986e-01, /* 0x3FD55555, 0x55555563 */
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1.33333333333201242699e-01, /* 0x3FC11111, 0x1110FE7A */
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5.39682539762260521377e-02, /* 0x3FABA1BA, 0x1BB341FE */
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2.18694882948595424599e-02, /* 0x3F9664F4, 0x8406D637 */
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8.86323982359930005737e-03, /* 0x3F8226E3, 0xE96E8493 */
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3.59207910759131235356e-03, /* 0x3F6D6D22, 0xC9560328 */
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1.45620945432529025516e-03, /* 0x3F57DBC8, 0xFEE08315 */
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5.88041240820264096874e-04, /* 0x3F4344D8, 0xF2F26501 */
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2.46463134818469906812e-04, /* 0x3F3026F7, 0x1A8D1068 */
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7.81794442939557092300e-05, /* 0x3F147E88, 0xA03792A6 */
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7.14072491382608190305e-05, /* 0x3F12B80F, 0x32F0A7E9 */
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-1.85586374855275456654e-05, /* 0xBEF375CB, 0xDB605373 */
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2.59073051863633712884e-05, /* 0x3EFB2A70, 0x74BF7AD4 */
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};
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#ifdef __STDC__
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double __kernel_tan(double x, double y, int iy)
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#else
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double __kernel_tan(x, y, iy)
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double x,y; int iy;
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#endif
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{
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double z,r,v,w,s;
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__int32_t ix,hx;
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GET_HIGH_WORD(hx,x);
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ix = hx&0x7fffffff; /* high word of |x| */
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if(ix<0x3e300000) { /* x < 2**-28 */
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if((int)x==0) { /* generate inexact */
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__uint32_t low;
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GET_LOW_WORD(low,x);
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if(((ix|low)|(iy+1))==0) return one/fabs(x);
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else {
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if(iy==1)
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return x;
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else {
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double a, t;
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z = w = x + y;
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SET_LOW_WORD(z,0);
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v = y - (z - x);
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t = a = -one / w;
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SET_LOW_WORD(t,0);
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s = one + t * z;
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return t + a * (s + t * v);
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}
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}
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}
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}
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if(ix>=0x3FE59428) { /* |x|>=0.6744 */
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if(hx<0) {x = -x; y = -y;}
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z = pio4-x;
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w = pio4lo-y;
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x = z+w; y = 0.0;
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}
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z = x*x;
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w = z*z;
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/* Break x^5*(T[1]+x^2*T[2]+...) into
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* x^5(T[1]+x^4*T[3]+...+x^20*T[11]) +
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* x^5(x^2*(T[2]+x^4*T[4]+...+x^22*[T12]))
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*/
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r = T[1]+w*(T[3]+w*(T[5]+w*(T[7]+w*(T[9]+w*T[11]))));
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v = z*(T[2]+w*(T[4]+w*(T[6]+w*(T[8]+w*(T[10]+w*T[12])))));
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s = z*x;
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r = y + z*(s*(r+v)+y);
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r += T[0]*s;
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w = x+r;
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if(ix>=0x3FE59428) {
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v = (double)iy;
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return (double)(1-((hx>>30)&2))*(v-2.0*(x-(w*w/(w+v)-r)));
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}
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if(iy==1) return w;
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else { /* if allow error up to 2 ulp,
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simply return -1.0/(x+r) here */
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/* compute -1.0/(x+r) accurately */
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double a,t;
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z = w;
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SET_LOW_WORD(z,0);
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v = r-(z - x); /* z+v = r+x */
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t = a = -1.0/w; /* a = -1.0/w */
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SET_LOW_WORD(t,0);
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s = 1.0+t*z;
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return t+a*(s+t*v);
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}
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}
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#endif /* defined(_DOUBLE_IS_32BITS) */
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