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Correct intel_syntax fsub* and fdiv* handling. Oh, how I'd like to be rid 

of UNIXWARE_COMPAT.
This commit is contained in:
Alan Modra 2000-02-24 12:40:45 +00:00
parent 9aa07a8f60
commit df256a94d6
1 changed files with 9 additions and 4 deletions
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13
include/opcode/i386.h
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@ -23,13 +23,15 @@ Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. */
gcc and possibly many other programs use this reversed syntax, so
we're stuck with it.
eg. `fsub %st(3),%st' results in st <- st - st(3) as expected, but
`fsub %st,%st(3)' results in st(3) <- st - st(3), rather than
the expected st(3) <- st(3) - st !
eg. `fsub %st(3),%st' results in st = st - st(3) as expected, but
`fsub %st,%st(3)' results in st(3) = st - st(3), rather than
the expected st(3) = st(3) - st
This happens with all the non-commutative arithmetic floating point
operations with two register operands, where the source register is
%st, and destination register is %st(i). Look for FloatDR below. */
%st, and destination register is %st(i). See FloatDR below.
The affected opcode map is dceX, dcfX, deeX, defX. */
#ifndef UNIXWARE_COMPAT
/* Set non-zero for broken, compatible instructions. Set to zero for
@ -64,6 +66,9 @@ static const template i386_optab[] = {
#define sld_FP (sld_Suf|IgnoreSize)
#define sldx_FP (sldx_Suf|IgnoreSize)
#if UNIXWARE_COMPAT
/* Someone forgot that the FloatR bit reverses the operation when not
equal to the FloatD bit. ie. Changing only FloatD results in the
destination being swapped *and* the direction being reversed. */
#define FloatDR FloatD
#else
#define FloatDR (FloatD|FloatR)