351 lines
8.3 KiB
Python
351 lines
8.3 KiB
Python
# -*- coding: utf-8 -*-
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"""Doctest for method/function calls.
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We're going the use these types for extra testing
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>>> from UserList import UserList
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>>> from UserDict import UserDict
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We're defining four helper functions
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>>> def e(a,b):
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... print a, b
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>>> def f(*a, **k):
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... print a, test_support.sortdict(k)
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>>> def g(x, *y, **z):
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... print x, y, test_support.sortdict(z)
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>>> def h(j=1, a=2, h=3):
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... print j, a, h
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Argument list examples
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>>> f()
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() {}
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>>> f(1)
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(1,) {}
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>>> f(1, 2)
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(1, 2) {}
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>>> f(1, 2, 3)
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(1, 2, 3) {}
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>>> f(1, 2, 3, *(4, 5))
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(1, 2, 3, 4, 5) {}
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>>> f(1, 2, 3, *[4, 5])
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(1, 2, 3, 4, 5) {}
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>>> f(1, 2, 3, *UserList([4, 5]))
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(1, 2, 3, 4, 5) {}
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Here we add keyword arguments
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>>> f(1, 2, 3, **{'a':4, 'b':5})
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(1, 2, 3) {'a': 4, 'b': 5}
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>>> f(1, 2, 3, *[4, 5], **{'a':6, 'b':7})
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(1, 2, 3, 4, 5) {'a': 6, 'b': 7}
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>>> f(1, 2, 3, x=4, y=5, *(6, 7), **{'a':8, 'b': 9})
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(1, 2, 3, 6, 7) {'a': 8, 'b': 9, 'x': 4, 'y': 5}
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>>> f(1, 2, 3, **UserDict(a=4, b=5))
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(1, 2, 3) {'a': 4, 'b': 5}
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>>> f(1, 2, 3, *(4, 5), **UserDict(a=6, b=7))
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(1, 2, 3, 4, 5) {'a': 6, 'b': 7}
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>>> f(1, 2, 3, x=4, y=5, *(6, 7), **UserDict(a=8, b=9))
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(1, 2, 3, 6, 7) {'a': 8, 'b': 9, 'x': 4, 'y': 5}
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Examples with invalid arguments (TypeErrors). We're also testing the function
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names in the exception messages.
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Verify clearing of SF bug #733667
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>>> e(c=4)
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Traceback (most recent call last):
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...
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TypeError: e() got an unexpected keyword argument 'c'
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>>> g()
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Traceback (most recent call last):
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...
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TypeError: g() takes at least 1 argument (0 given)
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>>> g(*())
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Traceback (most recent call last):
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...
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TypeError: g() takes at least 1 argument (0 given)
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>>> g(*(), **{})
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Traceback (most recent call last):
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...
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TypeError: g() takes at least 1 argument (0 given)
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>>> g(1)
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1 () {}
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>>> g(1, 2)
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1 (2,) {}
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>>> g(1, 2, 3)
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1 (2, 3) {}
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>>> g(1, 2, 3, *(4, 5))
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1 (2, 3, 4, 5) {}
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>>> class Nothing: pass
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...
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>>> g(*Nothing())
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Traceback (most recent call last):
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...
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TypeError: g() argument after * must be an iterable, not instance
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>>> class Nothing:
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... def __len__(self): return 5
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...
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>>> g(*Nothing())
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Traceback (most recent call last):
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...
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TypeError: g() argument after * must be an iterable, not instance
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>>> class Nothing():
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... def __len__(self): return 5
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... def __getitem__(self, i):
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... if i<3: return i
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... else: raise IndexError(i)
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...
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>>> g(*Nothing())
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0 (1, 2) {}
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>>> class Nothing:
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... def __init__(self): self.c = 0
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... def __iter__(self): return self
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... def next(self):
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... if self.c == 4:
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... raise StopIteration
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... c = self.c
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... self.c += 1
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... return c
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...
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>>> g(*Nothing())
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0 (1, 2, 3) {}
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Check for issue #4806: Does a TypeError in a generator get propagated with the
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right error message?
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>>> def broken(): raise TypeError("myerror")
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...
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>>> g(*(broken() for i in range(1)))
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Traceback (most recent call last):
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...
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TypeError: myerror
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Make sure that the function doesn't stomp the dictionary
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>>> d = {'a': 1, 'b': 2, 'c': 3}
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>>> d2 = d.copy()
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>>> g(1, d=4, **d)
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1 () {'a': 1, 'b': 2, 'c': 3, 'd': 4}
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>>> d == d2
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True
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What about willful misconduct?
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>>> def saboteur(**kw):
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... kw['x'] = 'm'
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... return kw
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>>> d = {}
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>>> kw = saboteur(a=1, **d)
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>>> d
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{}
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>>> g(1, 2, 3, **{'x': 4, 'y': 5})
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Traceback (most recent call last):
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...
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TypeError: g() got multiple values for keyword argument 'x'
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>>> f(**{1:2})
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Traceback (most recent call last):
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...
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TypeError: f() keywords must be strings
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>>> h(**{'e': 2})
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Traceback (most recent call last):
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...
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TypeError: h() got an unexpected keyword argument 'e'
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>>> h(*h)
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Traceback (most recent call last):
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...
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TypeError: h() argument after * must be an iterable, not function
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>>> h(1, *h)
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Traceback (most recent call last):
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...
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TypeError: h() argument after * must be an iterable, not function
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>>> dir(*h)
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Traceback (most recent call last):
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...
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TypeError: dir() argument after * must be an iterable, not function
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>>> None(*h)
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Traceback (most recent call last):
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...
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TypeError: NoneType object argument after * must be an iterable, \
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not function
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>>> h(**h)
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Traceback (most recent call last):
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...
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TypeError: h() argument after ** must be a mapping, not function
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>>> h(**[])
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Traceback (most recent call last):
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...
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TypeError: h() argument after ** must be a mapping, not list
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>>> h(a=1, **h)
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Traceback (most recent call last):
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...
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TypeError: h() argument after ** must be a mapping, not function
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>>> h(a=1, **[])
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Traceback (most recent call last):
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...
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TypeError: h() argument after ** must be a mapping, not list
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>>> dir(**h)
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Traceback (most recent call last):
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...
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TypeError: dir() argument after ** must be a mapping, not function
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>>> None(**h)
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Traceback (most recent call last):
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...
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TypeError: NoneType object argument after ** must be a mapping, \
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not function
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>>> dir(b=1, **{'b': 1})
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Traceback (most recent call last):
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...
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TypeError: dir() got multiple values for keyword argument 'b'
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Another helper function
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>>> def f2(*a, **b):
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... return a, b
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>>> d = {}
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>>> for i in xrange(512):
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... key = 'k%d' % i
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... d[key] = i
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>>> a, b = f2(1, *(2,3), **d)
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>>> len(a), len(b), b == d
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(3, 512, True)
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>>> class Foo:
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... def method(self, arg1, arg2):
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... return arg1+arg2
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>>> x = Foo()
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>>> Foo.method(*(x, 1, 2))
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3
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>>> Foo.method(x, *(1, 2))
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3
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>>> Foo.method(*(1, 2, 3))
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Traceback (most recent call last):
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...
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TypeError: unbound method method() must be called with Foo instance as \
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first argument (got int instance instead)
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>>> Foo.method(1, *[2, 3])
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Traceback (most recent call last):
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...
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TypeError: unbound method method() must be called with Foo instance as \
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first argument (got int instance instead)
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A PyCFunction that takes only positional parameters should allow an
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empty keyword dictionary to pass without a complaint, but raise a
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TypeError if te dictionary is not empty
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>>> try:
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... silence = id(1, *{})
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... True
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... except:
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... False
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True
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>>> id(1, **{'foo': 1})
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Traceback (most recent call last):
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...
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TypeError: id() takes no keyword arguments
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A corner case of keyword dictionary items being deleted during
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the function call setup. See <http://bugs.python.org/issue2016>.
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>>> class Name(str):
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... def __eq__(self, other):
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... try:
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... del x[self]
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... except KeyError:
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... pass
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... return str.__eq__(self, other)
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... def __hash__(self):
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... return str.__hash__(self)
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>>> x = {Name("a"):1, Name("b"):2}
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>>> def f(a, b):
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... print a,b
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>>> f(**x)
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1 2
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An obscure message:
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>>> def f(a, b):
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... pass
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>>> f(b=1)
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Traceback (most recent call last):
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...
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TypeError: f() takes exactly 2 arguments (1 given)
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The number of arguments passed in includes keywords:
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>>> def f(a):
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... pass
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>>> f(6, a=4, *(1, 2, 3))
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Traceback (most recent call last):
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...
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TypeError: f() takes exactly 1 argument (5 given)
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"""
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import unittest
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import sys
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from test import test_support
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class ExtCallTest(unittest.TestCase):
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def test_unicode_keywords(self):
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def f(a):
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return a
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self.assertEqual(f(**{u'a': 4}), 4)
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self.assertRaises(TypeError, f, **{u'stören': 4})
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self.assertRaises(TypeError, f, **{u'someLongString':2})
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try:
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f(a=4, **{u'a': 4})
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except TypeError:
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pass
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else:
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self.fail("duplicate arguments didn't raise")
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def test_main():
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test_support.run_doctest(sys.modules[__name__], True)
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test_support.run_unittest(ExtCallTest)
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if __name__ == '__main__':
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test_main()
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