#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
using namespace std;
const double inf = 1e100, EPS = 1e-8;
const int N = 101;
double l, now;
int n,t;
struct edge
{
	double x[2], y[2];
} e[N];
// WA double 判断正负要用
int sign(double d)
{
	if (fabs(d) < EPS)
	{
		return 0;
	}
	else
		return d > 0 ? 1 : -1;
}
double cross(double x1, double y1, double x2, double y2)
{
	return x1 * y2 - x2 * y1;
}
int same(double x0, double y0, double x3, double y3, double x1, double y1, double x2, double y2)
{
	double x = x3 - x0, y = y3 - y0; // y0->x0
	//WA？ 没有用浮点数的大小比较方法 
	return sign(cross(x, y, x1 - x0, y1 - y0)) * sign(cross(x, y, x2 - x0, y2 - y0));
}
//与所有边比是否相交
bool ob(int x0, int y0, int x1, int y1)
{
	for (int i = 1; i <= n; i++)
	{
		if (sign(same(x0,y0,x1,y1,e[i].x[0],e[i].y[0],e[i].x[1],e[i].y[1])) > 0)
		{
			return 0;
		}
	}
	return 1;
}
//另一线段的点，连点成线
bool dot2(int ii, int jj)
{
	for (int i = 1; i <= n; i++)
	{
		if (i == ii)
			continue;
		for (int j = 0; j < 2; j++)
		{
			if(sign(e[ii].x[jj]-e[i].x[j])==0&&sign(e[ii].y[jj]-e[i].y[j])==0) continue;
			if (ob(e[ii].x[jj], e[ii].y[jj], e[i].x[j], e[i].y[j]))
			{
				return 1;
			}
		}
	}
	return 0;
}
//找一个点
bool adot()
{
	for (int i = 1; i <= n; i++)
	{
		for (int j = 0; j < 2; j++)
		{
			if (dot2(i, j))
			{
				return 1;
			}
		}
	}
	return 0;
}
int main()
{
	scanf("%d", &t);
	while (t--)
	{
		scanf("%d", &n);
		memset(&e, 0, sizeof(edge) * (n + 1));
		for (int i = 1; i <= n; i++)
		{
			for (int j = 0; j < 2; j++) // 又是j
			{
				scanf("%lf%lf", &e[i].x[j], &e[i].y[j]);//少一个%lf 
			}
		}
		if(n==1)
		{
			printf("Yes!\n");
			continue;
		 } 
		if(adot())
		{
			printf("Yes!\n");
		}
		else
		{
			printf("No!\n");
		}
	}
	return 0;
}