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你，n

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ljcjames 2022-08-19 08:27:32 +08:00
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8.16/M-PairsFormingLCM/Readme.md
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@ -5,7 +5,7 @@
### 做法
质因数分解n=p1^k1*p2^k2
ans*=(2k[i]+1);(i=0~k,j=0~k,去掉重复的k,k)
ans=ans/2+1;(i<=j,补上k,k)
ans=ans/2+1;(i<=j,补上n,n，因为只出现了一次)
### 关键词
### 易错点