“借鉴”别人的

This commit is contained in:
ljcjames 2022-08-12 16:44:44 +08:00
parent 349b318ffd
commit 8ef2e29769
1 changed files with 57 additions and 41 deletions

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@ -1,65 +1,81 @@
//参考别人的
#include <iostream>
#include <cmath>
#include <cstdio>
#include <algorithm>
#include<stack>
using namespace std;
const double pi=acos(-1.00),eps = 1e-6;//pi3.14~
const int N=1001,inf=0x3f3f3f3f;
const double pi=acos(-1.00),eps = 1e-8;//pi3.14~
const int N=1005,inf=0x3f3f3f3f;
double ans=0;
struct dot{
int x,y;
}d[N];
stack<int>s;
int q[N],n;
struct Point{
double x,y;
Point () {}//无参的构造函数,及初始化、赋初值
Point (double xx,double yy) :x(xx),y(yy) {}
Point friend operator - (Point a,Point b)
{
return Point(a.x-b.x,a.y-b.y);
}
double friend operator ^ (Point a,Point b)
{
return a.x*b.y-a.y*b.x;
}
bool friend operator < (Point a,Point b)
{
if(a.y==b.y ) return a.x<b.x;
return a.y<b.y;
}
}p[N];
//stack<int>s;
int sign(double d)
{
if(fabs(d)<eps) return 0;
return d>0? 1:-1;
}
double cross(double x1, double y1, double x2, double y2)
//double cross(double x1, double y1, double x2, double y2)
//{
// return x1 * y2 - x2 * y1;
//}
double dist(Point a,Point b)
{
return x1 * y2 - x2 * y1;
Point c=a-b;
return sqrt(c.x*c.x+c.y*c.y);//CE double
}
double length(int x1,int y1,int x2,int y2)
bool cmp(Point a,Point b)
{
int x=x1-x2,y=y1-y2;
return sqrt((double)x*x+y*y);//CE double
int s=sign((a-p[1])^(b-p[1]));
if(s>0||(s==0&&dist(a,p[1])<dist(b,p[1])))return 1;
else return 0;
}
double Graham()
{
sort(p+1,p+n+1);
sort(p+1,p+1+n,cmp);
int top=3;
q[1]=1,q[2]=2,q[3]=3;
for(int i=4;i<=n;i++)
{
while(top>1&&sign((p[q[top]]-p[q[top-1]])^(p[i]-p[q[top]]))<=0){
top--;
}
q[++top]=i;
}
double res=0;
for(int i=1;i<top;i++)
{
res+=dist(p[q[i]],p[q[i+1]]);
}
return res+dist(p[q[1]],p[q[top]]);
}
int main()
{
int n,l,minn=1,f,ff,x0,x1,x2,y1,y2,y0;
int l,minn=1,f,ff,x0,x1,x2,y1,y2,y0;
scanf("%d%d",&n,&l);
for(int i=1;i<=n;i++)
{
scanf("%d%d",&d[i].x,&d[i].y);//&!!!
minn=d[i].y<d[minn].y? i:minn;
scanf("%lf%lf",&p[i].x,&p[i].y);//&!!!
}
int j=(n+minn-2)%n+1;
// s.push(minn%n+1);
s.push(minn);
s.push(j);
ans+=length(d[j].x,d[j].y,d[minn].x,d[minn].y);//漏了初始的边
while(j!=minn)
{
j=(j+n-2)%n+1;
f=s.top();
s.pop();
ff=s.top();
while(0>=sign(cross(d[f].x-d[ff].x,d[f].y-d[ff].y,d[j].x-d[ff].x,d[j].y-d[ff].y)))
{
ans-=length(d[f].x,d[f].y,d[ff].x,d[ff].y);
// printf("--%d(%d,%d),%d(%d,%d): -%lf=%lf\n",f,d[f].x,d[f].y,ff,d[ff].x,d[ff].y,length(d[f].x,d[f].y,d[ff].x,d[ff].y),ans);
f=s.top();
s.pop();
if(s.empty()) break;//RE
ff=s.top();
}
ans+=length(d[j].x,d[j].y,d[f].x,d[f].y);
// printf("++%d(%d,%d),%d(%d,%d): +%lf=%lf\n",j,d[j].x,d[j].y,f,d[f].x,d[f].y,length(d[j].x,d[j].y,d[f].x,d[f].y),ans);
s.push(f);
s.push(j);
}
// printf("%d ",s.size());
printf("%.0lf",ans+2*l*pi);//WA*2 (周长跟多边形形状有关)错了,无关,自带四舍五入
printf("%d",(int)(Graham()+pi*2*l+0.5));//(int)()记得加括号
return 0;
}